matlab code newton rapson method:

 newton rapson method:

Programme:

f=@(x) 30-15*(1/exp(.5*x))

f1=@(x) (7.5/exp(.5*x))

x1=0;

for i=0:1:10

x2=x1-(f(x1)/f1(x1));

if f(x2)==0

break;

else

x1=x2;

end

end

x2

MATLAB Running:

>> raph

f  = @(x)30-15*(1/exp(.5*x))

f1 = @(x)(7.5/exp(.5*x))

x2 = -1.3863

>>